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PLEASE HELP!!!

A sample of xenon occupies a volume of 715 mL at 8.01 atm and 67 °C. If the volume is changed to 963 mL and the temperature is changed to 52 °C, what will
be the new pressure?

1 Answer

1 vote

Answer:

4.62 atm

Step-by-step explanation:

To find the missing pressure, you need to use the Combined Gas Law equation:

P₁V₁ / T₁ = P₂V₂ / T₂

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature.

P₁ = 8.01 atm P₁ = ? atm

V₁ = 715 mL V₁ = 963 mL

T₁ = 67 °C T₁ = 52 °C

P₁V₁ / T₁ = P₂V₂ / T₂

(8.01 atm)(715 mL) / 67 °C = P₂(963 mL) / 52 °C

85.47985 = P₂(963 mL) / 52 °C

4444.952 = P₂(936 mL)

4.62 atm = P₂

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