Question

A tank of water contains 35 liters of water that leaks 6 liters of water an hour another container contains 29 liters of water that leaks 3 an hour if no the the tank and container start leaking at the same time how long does it takes for both the tank and container to have the same amount of water

Answer 1

Explanation:

Let the # of liters in both containers = y when equality is reached.

Container 1: loses 6 liters / hour

Container 2: loses 3 liters / hour

Equation

35 - 6x = 29 - 3x

Solution

35 - 6x = 29 - 3x Subtract 29 from both sides

35 - 29 - 6x = 29 - 29 - 3x Combine

6 - 6x = - 3x Add 6x to both sides

6 - 6x + 6x = - 3x + 6x Combine

6 = 3x Divide both sides by 3

6/3 = 3x/3

2 = x

After 2 hours they should have the same amount of water.

35 - 6(2) = 35 - 12 = 23

29 - 3*2 = 29 - 6 = 23

Answer

After 2 hours have passed, both containers should have 23 Liters each.