Question

What is an equation of the line that passes through the points (-3, 1) and (-6, 3)?

Answer 1

y=-2/3x-1

Explanation:

m=(y2-y1)/(x2-x1)

m=(3-1)/(-6-(-3))

m=2/(-6+3)

m=2/-3

m=-2/3

y-y1=m(x-x1)

y-1=-2/3(x-(-3))

y-1=-2/3(x+3)

y=-2/3x-6/3+1

y=-2/3x-2+1

y=-2/3x-1