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Geometry question confused on how to solve this answer

Geometry question confused on how to solve this answer-example-1
User Romello
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1 Answer

1 vote

The acute angles of a right triangle are complementary, so
\boxed{m\angle F=34^(\circ)}.

Using right-angle trigonometry, we know that


\cos 56^(\circ)=(26)/(DF)\\\\DF=(26)/(\cos 56^(\circ))\\\\\boxed{DF \approx 46.5}


\tan 56^(\circ)=(FE)/(26)\\\\FE=26 \tan 56^(\circ)\\\\\boxed{FE \approx 38.5}