Question

If someone can help with this that would be great

Answer 1

`\fbox {p = 7.3 m}`

Explanation:

Applying the Law of Sines :

`\boxed {(sin R)/(PS) = (sin P)/(RS)}`

Substitute the values :

• sin 62° / 10 = sin 40° / p
• p = sin 40° × 10 / sin 62°
• p = 0.64278761 × 10 / 0.882947593
• p = 7.3 m (nearest tenth)

Answer 2

p ≈ 7.3 m

Explanation:

using the Sine Rule in the triangle

`(p)/(sinP)` =
`(r)/(sinR)` ( substitute values )

`(p)/(sin40)` =
`(10)/(sin62)` ( cross- multiply )

p × sin62° = 10 × sin40° ( divide both sides by sin62° )

p =
`(10sin40)/(sin62)` ≈ 7.3 m ( to the nearest tenth )