Question

In a bag of 10 marbles, there are 4 blue, 3 red, 2 green,

and 1 yellow. What is the probability that you draw one
marble that is red, replace it, and draw another marble that
is yellow?
a. 2
-
5
b. 3
100
C. 1
30
O d. 3
10

Answer 1

c. 3/100

Explanation:

there are 10 marbles

First draw (there are 3 red marbles)

`P=(3)/(10)`

Second draw (there is one yellow marble)

`P=(1)/(10)`

probability of the event:

`P=((3)/(10) )((1)/(10) )=(3)/(100)`

Hope this helps

Answer 2

`P(R \: then \: Y) = (3)/(10) * (1)/(10) = (3)/(100)`

`note \: that = \\ order \: matters \: (no \: factorial) \\ replacement \: (equal \: sample \: space)`

Option B