Given points (8,6) and ( 8, 0) as the endpoints of a radius ,what is the equation of the circle with center ( 8,6)

Question

asked Jul 6, 2023 234k views

1 Answer

Baspa · Answer 1 · 2023-07-11T16:59:30+0000

The general equation of a circle is written like
(x-h)^2+(y-k)^2=r^2 , where (h,k) is the centre and r is the radius.

Firstly, we're given that the centre is (8,6).

Plug this into the general equation:

$(x-h)^2+(y-k)^2=r^2\\(x-8)^2+(y-6)^2=r^2$

We're given this other point on the circumference of the circle, (8,0), which is 6 units away from the center.

Therefore, the radius is 6 units. Plug this into the general equation too:

$(x-8)^2+(y-6)^2=r^2\\(x-8)^2+(y-6)^2=6^2\\(x-8)^2+(y-6)^2=36$

(x-8)^2+(y-6)^2=36