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given points (8,6) and ( 8, 0) as the endpoints of a radius ,what is the equation of the circle with center ( 8,6)

User BLC
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Circle Equations

The general equation of a circle is written like
(x-h)^2+(y-k)^2=r^2, where (h,k) is the centre and r is the radius.

Solving the Question

Firstly, we're given that the centre is (8,6).

Plug this into the general equation:


(x-h)^2+(y-k)^2=r^2\\(x-8)^2+(y-6)^2=r^2

We're given this other point on the circumference of the circle, (8,0), which is 6 units away from the center.

Therefore, the radius is 6 units. Plug this into the general equation too:


(x-8)^2+(y-6)^2=r^2\\(x-8)^2+(y-6)^2=6^2\\(x-8)^2+(y-6)^2=36

Answer


(x-8)^2+(y-6)^2=36

User Baspa
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