Question

A canon ball is shot out of a cannon at an angle of 45 degrees. What is the initial velocity of the cannon ball if its initial horizontal velocity is 8 m/s?

Answer 1

11.31 [m/s].

Step-by-step explanation:

1. the required velocity can be calculated according to

`V=(V_(horizontal))/(sin45);`

2. according to the formula above:

V=8*1.41≈11.3137085 [m/s].