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A canon ball is shot out of a cannon at an angle of 45 degrees. What is the initial velocity of the cannon ball if its initial horizontal velocity is 8 m/s?
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A canon ball is shot out of a cannon at an angle of 45 degrees. What is the initial velocity of the cannon ball if its initial horizontal velocity is 8 m/s?

User Pheobe
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1 Answer

6 votes

Answer:

11.31 [m/s].

Step-by-step explanation:

1. the required velocity can be calculated according to


V=(V_(horizontal))/(sin45);

2. according to the formula above:

V=8*1.41≈11.3137085 [m/s].

User Cosmincalistru
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