Question

The area of a rectangle is 44 ft², and the

Length of the rectangle is 3 ft less than twice
The width. Find the dimensions of the rectangle.

Answer 1

Width = 5.5ft, Length = 8ft.

Explanation:

Area of Rectangle = Length x Width

Let w be the Width of the rectangle.

From the information given from the question,

Length = 2w - 3 (3ft less than twice the width)

Area of Rectangle =
`(2w-3)w\\=2w^(2) -3w` = 44

Now we can solve for w to find the dimensions.

`2w^(2) -3w-44=0` (Quadratic Equations)

We can use the Quadratic formula to find w.

`w=\frac{-b+/-\sqrt{b^(2)-4ac } }{2a}`

Since a = 2, b = -3 and c = -44,

`w=\frac{-(-3)+/-\sqrt{(-3)^(2)-4(2)(-44) } }{2(2)} \\= 5.5 or -4 (reject)`

We reject negative values here.

Therefore, the width of the Rectangle = 5.5ft

While the length of the rectangle = 2(5.5) - 3 = 11 - 3 = 8ft