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A weather balloon calibrated at 0.00 °C to

have a volume of 20.0 L has what volume at
-36.2 °C assuming pressure is held
constant? Answer is in L

User Spamguy
by
3.9k points

1 Answer

4 votes

Answer:

17.3 L

Step-by-step explanation:

With all other variables held constant, you can find the missing volume using the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. Before we can solve, we need to convert Celsius to Kelvin (because we don't want negative numbers or temp. of 0).

V₁ = 20.0 L V₂ = ? L

T₁ = 0.00 °C + 273.15 = 273.15 K T₂ = -36.2 °C + 273.15 = 236.95 K

V₁ / T₁ = V₂ / T₂ <----- Charles' Law equation

20.0 L / 273.15 K = V₂ / 236.95 K <----- Insert values

0.0732 = V₂ / 236.95 K <----- Simplify left side

17.3 L = V₂ <----- Multiply both sides by 236.95

User Stefan Zhelyazkov
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5.8k points