68.2k views
3 votes
PLEASE HELPPPPPPPPPPPPPPPPPPPPPPP

PLEASE HELPPPPPPPPPPPPPPPPPPPPPPP-example-1

2 Answers

7 votes

Answer:

x intercepts: (1,0), (-3,0)

the roots are 1 and -3

Explanation:

Using the Quadratic Formula:

x=−b±sqrt(b2−4ac)/2a

Substitute:

x= -8±sqrt(8^2-4(4)(-12))/2(4)

x=-8±sqrt((64- -192))/8

x=-8±sqrt(256)/8

Solve two equations (±)

x=-8±16/8

x=8/8 and x=-24/8

x=1 and x=-3

User Breddy
by
7.7k points
6 votes

Answer:

x = -3

x = 1

Explanation:

Hello!

We can solve the quadratic by Factoring the Equation and using the Zero Product Property.

Factor


  • y = 4x^2 + 8x - 12

  • y = 4(x^2 + 2x - 3)

We want to find two numbers that multiply out to -3, but add up to 2. The numbers that work are -1 and 3. We can expand 2x to -x and 3x and factor by grouping.


  • y = 4(x^2 -x + 3x - 3)

  • y = 4(x(x - 1) + 3(x - 1))

  • y = 4(x + 3)(x - 1)

Solve for x

Set each factor to 0 and solve for x in both.


  • 0 = 4(x + 3)(x - 1)

  • 0 = (x + 3), x = -3

  • 0 = (x - 1), x = 1

Therefore, the x-interecpts are -3 and 1.

User Mareza
by
9.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories