Question

Need help!!! Thanks!!!
Pre-Cal
27^(2x) = (1/9)^(x-1)

Answer 1

`x = (1)/(4)\\`

Explanation:

Given:

`27^(2x) = ((1)/(9))^(x-1)\\`

Rewriting your equation:

`((1)/(27))^(-2x) = ((1)/(9))^(x-1) \\ (((1)/(3))^3)^(-2x) = (((1)/(3))^2)^(x-1) \\ ((1)/(3))^(-6x) = ((1)/(3))^(2(x-1))`

Disregard same bases:

`-6x = 2(x -1)`

Solve for
`x`:

`-6x = 2x -2 \\ -8x = -2 \\ x = (1)/(4)`