Question

Consider the equation 4x^4 - 38x^3 = 17x^2 + 30x. One of the real solutions to the equation is 10. What are the other solutions, both real and nonreal

Answer 1

Answer: Option (1)

Explanation:

`4x^4 -38x^3 -17x^2 -30x=0`

Dividing both sides by
`x-10` (10 is a root, so x-10 is a factor), yields

`4x^3 +2x^2 +3x=0\\\\x(4x^2 +2x+3)=0\\\\x=0, 4x^2 +2x+3=0`

Solving the second case by the quadratic formula yields
`x=(-1 \pm i√(11))/(4)`.

So, the answer is Option (1).