How fast was a driver going if the car left skid marks that were 48 feet long on dry concrete? (The coefficient of friction is 1.02)? A) 31 mph B) 38 mph C) 49 mph D) 73 mph

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Viktor Sec asked Nov 4, 2023

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How fast was a driver going if the car left skid marks that were 48 feet long on dry concrete? (The coefficient of friction is 1.02)?

A) 31 mph
B) 38 mph
C) 49 mph
D) 73 mph

Mathematics
high-school

Viktor Sec asked Nov 4, 2023

by Viktor Sec

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Answer:

B) 38 mph

Explanation:

s = √(30df)

s is the speed the car was traveling (in mph)

d is the distance the car skidded (in feet)

f is the coefficient of friction

s = √(30 x 48 x 1.02)

s = 38.32492661... = 38

Jeff Saltfist answered Nov 10, 2023

by Jeff Saltfist

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