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Find the zeros of the function: f(x)=-2x(x+7)+10x+70

1 Answer

6 votes

Answer:


x=\displaystyle(3\pm√(569))/(4)

Explanation:

Hi there!


f(x) = -2x(x+7)+10x+70\\f(x) = -2x^2-7x+10x+70\\f(x) = -2x^2+3x+70

We can solve this by using the quadratic formula, which states:


x=\displaystyle(-b\pm√(b^2-4ac))/(2a) where
f(x)=ax^2+bx+c

Plug in the values a, b and c:


x=\displaystyle(-3\pm√(3^2-4(-2)(70)))/(2(-2))\\\\x=\displaystyle(-3\pm√(9+560))/(-4)\\\\x=\displaystyle(-3\pm√(569))/(-4)\\\\x=\displaystyle(3\pm√(569))/(4)

I hope this helps!

User Nurdyguy
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