Question

Ppppp-pp help please.

Answer 1

There are two complex roots:

• 
  `-3\pm i`

============

Given equation:

• x² - 6x + 10 = 0

The standard form is:

• ax² + bx + c = 0

Compared we can find values of the coefficients and the constant:

• a = 1, b = - 6, c = 10

Substitute these values into quadratic formula:

`x=(-b\pm√(b^2-4ac) )/(2a)`

and work out roots:

`x=(-(-6)\pm√((-6)^2-4*1*10) )/(2*1)=x=(6\pm√(36-40) )/(2)=(6\pm2√(-1) )/(2)=3 \pm i`