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Ppppp-pp help please.

Ppppp-pp help please.-example-1
User Sigcont
by
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1 Answer

3 votes

Answer:

There are two complex roots:


  • -3\pm i

============

Given equation:

  • x² - 6x + 10 = 0

The standard form is:

  • ax² + bx + c = 0

Compared we can find values of the coefficients and the constant:

  • a = 1, b = - 6, c = 10

Substitute these values into quadratic formula:


x=(-b\pm√(b^2-4ac) )/(2a)

and work out roots:


x=(-(-6)\pm√((-6)^2-4*1*10) )/(2*1)=x=(6\pm√(36-40) )/(2)=(6\pm2√(-1) )/(2)=3 \pm i

User Eliasz Kubala
by
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