Question

Write down the equation of the straight line which passes through (0, -3) and parallel to the straight line y = -2x+1​

Answer 1

y = -2x - 3

Explanation:

Equation of line:

Parallel lines have same slope.

y = -2x + 1

Compare with the equation of line in slope intercept form y = mx + b

Here m is the slope and b is the y -intercept

m = -2

m = -2 ; line passes through (0 , -3)

Equation of line in slope intercept form:

`\sf \boxed{\bf y - y_1=m(x-x_1)}`

y - [-3] = -2(x - 0)

y +3 = -2x

y = -2x - 3