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A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the pressure is increased to 10.5 atm?

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Answer:

45.8 mL

Step-by-step explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm P₂ = 10.5 atm

V₁ = 155 mL V₂ = ? mL

P₁V₁ = P₂V₂ <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂ <----- Insert values

480.5 = (10.5 atm)V₂ <----- Multiply 3.1 and 155

45.8 = V₂ <----- Divide both sides by 10.5

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