33.6k views
1 vote
A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the pressure is increased to 10.5 atm?

1 Answer

3 votes

Answer:

45.8 mL

Step-by-step explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm P₂ = 10.5 atm

V₁ = 155 mL V₂ = ? mL

P₁V₁ = P₂V₂ <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂ <----- Insert values

480.5 = (10.5 atm)V₂ <----- Multiply 3.1 and 155

45.8 = V₂ <----- Divide both sides by 10.5

User QuantIbex
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.