Question

1. The fractions

below are all
equivalent. Find the
values of n t and k.
3/7 12/n t/21 k-1/2k+10

Answer 1

3/7 =12/n

3n=7×12

3n=84

n=84÷3

n=28

3/7= t/21

3×21=7t

63=7t

t=63÷7

t=9

3/7 =k-1/2k+10

3(2k+10)=7(k-1)

6k+30=7k-7

k=37

Explanation: