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Question 1 (1 point) m2IJK-570 and mZIJL-20°. Find mZLJK. 3 →K O a MZLJK-77° Ob mZLJK-37° Oc mZLJK-40° Od mZLJK=-37°

Question 1 (1 point) m2IJK-570 and mZIJL-20°. Find mZLJK. 3 →K O a MZLJK-77° Ob mZLJK-37° Oc mZLJK-40° Od mZLJK=-37°
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3 votes
Question 1 (1 point)

m2IJK-570 and mZIJL-20°. Find mZLJK.
3
→K
O a MZLJK-77°
Ob mZLJK-37°
Oc mZLJK-40°
Od mZLJK=-37°

Question 1 (1 point) m2IJK-570 and mZIJL-20°. Find mZLJK. 3 →K O a MZLJK-77° Ob mZLJK-example-1
User Jithin Raj P R
by
8.3k points

1 Answer

4 votes

Answer:

37°

Explanation:

Subtract angle IJL from angle IJK.

User Bernesto
by
8.5k points
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