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Find equation of the line passing through the point (-1,0) and parallel to the line y=-1/2x + 3/7

User Nick Soper
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1 Answer

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Answer:

Explanation:

A parallel line will have the same slope, m, as the reference line given by the form y=mx+b. b is the y-intercept, the value of y when x=0.

The reference line of y = -(1/2)x + (3/7) has a slope of -(1/2).

The parallel line will have the same slope, so we can write:

y - -(1/2)x + b

We need a value of b that forces the line to go through point (-1,0). Enter that point in the equation and solve for b:

y - -(1/2)x + b

0 - -(1/2)(-1) + b

b = -(1/2)

The equation of the line parallel to y = -(1/2)x + (3/7) and going through (-1,0) is

y=-(1/2)x - (1/2)

Find equation of the line passing through the point (-1,0) and parallel to the line-example-1
User Trante
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