197k views
1 vote
What is the slope of a line passing through (-5, 5) and
(-4, 10)?

User Zrb
by
7.7k points

2 Answers

3 votes

Answer:

Slope = 5

Explanation:

Slope:

(-5,5) ; x₁ = -5 & y₁ = 5

(-4, 10) ; x₂ = -4 & y₂ = 10


\sf \boxed{\bf Slope = (y_2-y_1)/(x_2-x_1)}


\sf =(10-5)/(-4-[-5])\\\\ =(10-5)/(-4+5)\\\\=(5)/(1)\\\\= 5

User Vortex
by
7.5k points
3 votes

Answer:

5

Explanation:

Formula for finding slope:


(y1 - y2)/(x1 - x2)

Slope of line passing through (-5,5) and (-4,10)

=


(5 - 10)/( - 5 - ( - 4)) \\ = ( - 5)/( - 5 + 4) \\ = ( - 5)/( - 1) \\ = 5

User Jgrant
by
7.8k points

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