Question

Write the standard form of the equation of the line trough the given point with the given slope.

Answer 1

Explanation:

we use the point-slope approach :

y - y1 = m(x - x1)

m is the slope, and (x1, y1) is a point on the line.

so,

1.

y - 2 = 7(x - 1) = 7x - 7

y = 7x - 5

2.

y - -1 = -1×(x - 3) = -x + 3

y + 1 = -x + 3

y = -x + 2

3.

y - 5 = -4(x - -2) = -4x - 8 (3x a "-" is a "-" for 8)

y = -4x - 3

4.

y - 5 = 5/3 × (x - 3) = 5x/3 - 5

y = 5x/3 or 5/3 × x

Answer 2

1.
`7x-y=5`

2.
`x+y=2`

3.
`4x+y=-3`

4.
`5x-3y=0`

Explanation:

Since we already know the slope and the coordinates of one point, first use the point-slope form to create an equation.

`y-k=m(x-h)`

`y-2=7(x-1)`

`y-2=7x-7`

`7x-y=5`

`y+1=-1(x-3)`

`y+1=-x+3`

`x+y=2`

`y-5=-4(x+2)`

`y-5=-4x-8`

`4x+y=-3`

`y-5=(5)/(3) (x-3)`

`y-5=(5)/(3)x-5`

`3y-15=5x-15`

`5x-3y=0`