Question

The length of a rectangle is 6 less than twice the width. If the perimeter is 60 inches, find the length and width.

Answer 1

w = 12

l = 18

Explanation:

Hello!

Recall the perimeter of a rectangle is twice the sum of the length and the width of the rectangle.

• 
  `P = 2(l + w)`

Let w be the width. The length is 6 less than twice the width. That means, l is 2w - 6.

Plug it into the formula and solve, given that P is 60.

Solve for w

• 
  `P = 2(l + w)`
• 
  `60 = 2(2w - 6 + w)`
• 
  `60 = 2(3w - 6)`
• 
  `60 = 6w - 12`
• 
  `72 = 6w`
• 
  `w = 12`

The width is 12 inches. We can plug in 12 for 2w - 6 to find the length.

Solve for l

• 
  `l = 2w - 6`
• 
  `l = 2(12) - 6`
• 
  `l = 24 - 6`
• 
  `l = 18`

The length is 18 inches.

The width is 12 inches, and the length is 18 inches.