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An oxygen gas tank holds 1 mole of gas at 10.0 atm of pressure. In order to reduce the pressure of the tank to 2.5 atm, moles must be released. How many moles will be left

User Noora
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1 Answer

5 votes

Answer:

0.25 moles

Step-by-step explanation:

To find the number of moles, you need to use a variation of the Ideal gas Law. The manipulated equation looks like this:

P₁ / n₁ = P₂ / n₂

In this formula, "P₁" and "n₁" represent the initial pressure and number of moles. "P₂" and "n₂" represent the final pressure and number of moles. You can find the final amount of moles by plugging the given values into the equation and simplifying.

P₁ = 10.0 atm P₂ = 2.5 atm

n₁ = 1 mole n₂ = ? moles

P₁ / n₁ = P₂ / n₂ <----- Equation

(10.0 atm) / (1 mole) = (2.5 atm) / n₂ <----- Insert values

10.0 = (2.5 atm) / n₂ <----- Divide 1 from 10.0

(10.0) x n₂ = 2.5 atm <----- Multiply both sides by n₂

n₂ = 0.25 <----- Divide both sides by 10.0

User Andi Schroff
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