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Practice 3

Solving a Special Solution inequality
17<3h+2<2
h>______
h <______

User Pulekies
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1 Answer

2 votes

Answer:

h > 5

h < 0

Explanation:

We suppose that a "Special Solution" inequality is one that is technically incorrect, but is written using a compact "shorthand" form.

As written, the inequality claims that 17 < 2, which is false. There can be no value of the variable that will make this true. We presume the intended meaning is ...

17 < 3h +2 or 3h +2 < 2

Special solution

Subtracting 2 from the inequality gives ...

15 < 3h < 0

Dividing by 3 gives ...

5 < h < 0

There is no value of h that is both greater than 5 and less than 0, so we presume this means the OR (union) of the solution sets ...

h > 5

h < 0

User Felastine
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