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MATH HELP!!! 100PTS!!!

Write the parametric equations

x=5sinθ,y=3cosθ,0≤θ≤π

in the given Cartesian form.

(y^2)/9=
with x≥0.

User Praneet
by
4.8k points

1 Answer

4 votes

Answer:


(y^2)/(9)=1-(x^2)/(25)

Explanation:

When converting parametric equations that involve trig functions to Cartesian equations, use trig identities to eliminate the parameter.

Given parametric equations:


x=5 \sin \theta, \quad y=3 \cos \theta, \quad 0\leq \theta\leq \pi

Square the equation for x:


\implies x^2=(5 \sin \theta)^2=25 \sin^2 \theta

Use the identity
\sin^2 x+\cos^2x =1 to write
x^2 in terms of cos:


\implies x^2=25(1-\cos^2 \theta)

Isolate
\cos^2 \theta :


\implies (x^2)/(25)=1-\cos^2 \theta


\implies \cos^2 \theta=1- (x^2)/(25)

Square the equation for y:


\implies y^2=(3 \cos \theta)^2=9 \cos ^2 \theta

Replace
\cos^2 \theta with the found equation involving
x^2 :


\implies y^2=9\left(1-(x^2)/(25)\right)

Divide both sides by 9:


\implies (y^2)/(9)=1-(x^2)/(25), \quad \textsf{with }x\geq 0

User Aniket Raj
by
4.8k points