Question

I haven't slept in 2 days and am so exhausted. Please if anyone could help... I have class in 2 hours and it's 3am rn

Answer 1

Solution:-

• a=Carbon(c)
• b=Nitrogen ion(N+)
• c=Oxygen ion(O-)

Now

#1

Let's look at the EC of carbon(Z=6)

`\\ \tt\longmapsto 1s^22s^22p^2`

• Valency is 4

Now.

3 electrons are shared(1 with H_3C and 2 with N+)

Hence

Electron left unshared=4-3=1

#2

Lets look at EC of Nitrogen(N),Z=7

`\\ \tt\longmapsto 1s^22s^22p^3`

• Valency is 3
• It has already shared 3 electrons

But

Its Cation i.e N+

• Hence 1 electron it donated .Now it has valency 4

Hence

Electron left unshared=4-3=1

#3

Lets look at EC of Oxygen(Z=8)

`\\ \tt\longmapsto 1s^22s^22p^4`

• Valency =2

But it is anion hence 1electron required more which us bonded

Hence

Number of electrons left unshared=0