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Find the area of following figure...?​

Find the area of following figure...?​-example-1
User Krakover
by
7.8k points

2 Answers

7 votes

Answer:

33,600 m^2.

Explanation:

This is a trapezium, so

Area = (h/2)(a + b)

= (h/2) ( 360 + 600)

= 960h / 2

= 480h,

We find the value of h using Pythagoras:

250^2 = h^2 + (600-360)^2

h^2 = 250^2 - 240^2 = 4900

h = 70.

So the Area = 70 * 480

= 33,600 m^2

User Xwlee
by
8.5k points
7 votes

Answer:

33600 m²

Explanation:

The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.

area of trapezoid = (a + b)h/2

where a and b are the lengths of the bases, and h is the height.

We need to find the height, BC.

Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.

DE + EC = DC

EC = AB = 360 m

DC = 600 m

DE + 360 m = 600 m

DE = 240 m

Use right triangle ADE to find AE. Then BC = AE.

DE² + AE² = AD²

DE² + 240² = 250²

DE² = 62500 - 57600

DE² = 4900

DE = √4900

DE = 70

BC = 70 = h

area = (a + b)h/2

area = (600 m + 360 m)(70 m)/2

area = 33600 m²

User Mfeineis
by
8.7k points

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