Question

Find the ratio of sinβ, cosβ and tanβ from given right angled triangle.

Answer 1

`\sin( \beta ) = (opposite)/(hypoten) = (ac)/(bc) \\ \cos( \beta ) = (adjascent)/(hypotenuse) = (ab)/(bc) \\ \tan( \beta ) = (opposite)/(adjacent) = (ac)/(ab) \\ thank \: you`

Answer 2

`\\ \sf\longmapsto sin\beta=(Perpendicular)/(Hypotenuse)=(AC)/(BC)`

`\\ \sf\longmapsto cos\beta=(Base)/(Hypotenuse)=(AB)/(BC)`

`\\ \sf\longmapsto tan\beta=(Perpendicular)/(Base)=(AC)/(AB)`