Question

If f(a) = 2a ^ 3 + 3a ^ 2 + 5 , find f(- 2)

Answer 1

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Answer
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f(-2)=1

Step-by-step explanation
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Given,

• Original Expression =
  `\sf{f(a)=2a^3+3a^2+5}`

To find,

• f(-2) = ??

All work is shown here. :))

`\Large\begin{gathered} \boldsymbol{\sf{Plug \ in \ the \ number \ for \ a, \ which \ is \ -2 (it's \ given \ to \ us). Then}}\\ \boldsymbol{\sf{evaluate,}} \\ \curvearrowright\\\boldsymbol{\sf{Now \ substitute \ -2}} \\\curvearrowright\\\sf{2(-2)^3+3(-2)^2+5}\\\sf{2*(-8)+3*4+5}\\\sf{}-16+12+5=-4+5}\\\underline{\boxed{\sf{f(-2)=1}}}\end{gathered}`

Done !!

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Answer 2

Answer: 1

Explanation:

Just plug in -2 anywhere you see an a

`f(a)=2a^3+3a^2+5\\f(-2)=2(-2)^3+3(-2)^2+5\\f(-2)=2(-8)+12+5\\f(-2)=-16+12+5\\f(-2)=1`