Question

Find any domain restrictions on the given rational equation

х/x+4 + 12/x^2 +5x+4 = 8x/5x-15
Select all that apply.
O A. x= -1
B. x = 0
C. x= 3
D. x = -4

Answer 1

`\\ \tt\hookrightarrow (x)/(x+4)+(12)/(x^2+5x+4)=(8x)/(5x-15)`

`\\ \tt\hookrightarrow (x)/(x+4)+(12)/((x+1)(x+4))=(8x)/(5(x-3))`

• For x=-4 First fraction becomes undefined
• For x=-1 second fraction becomes undefined
• For x=3 third fraction also becomes undefined

So Domain=(-4,-1,3)

Answer 2

x ≠ -4, -1, 3

Explanation:

`(x)/(x+4)+ (12)/(x^2) +5x+4 = (8x)/(5x-15)`

`12/(x^2+5x+4) = 8x/(5x-15)`

`(12)/(((x+1)(x+4))) = (8x)/((5(x-3)))`