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27 votes
27 votes
Find any domain restrictions on the given rational equation

х/x+4 + 12/x^2 +5x+4 = 8x/5x-15
Select all that apply.
O A. x= -1
B. x = 0
C. x= 3
D. x = -4

User Mayur Gangurde
by
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2 Answers

19 votes
19 votes


\\ \tt\hookrightarrow (x)/(x+4)+(12)/(x^2+5x+4)=(8x)/(5x-15)


\\ \tt\hookrightarrow (x)/(x+4)+(12)/((x+1)(x+4))=(8x)/(5(x-3))

  • For x=-4 First fraction becomes undefined
  • For x=-1 second fraction becomes undefined
  • For x=3 third fraction also becomes undefined

So Domain=(-4,-1,3)

User Jo Kristian Bergum
by
2.8k points
22 votes
22 votes

Answer:

x ≠ -4, -1, 3

Explanation:


(x)/(x+4)+ (12)/(x^2) +5x+4 = (8x)/(5x-15)


12/(x^2+5x+4) = 8x/(5x-15)


(12)/(((x+1)(x+4))) = (8x)/((5(x-3)))

User Pouya
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2.9k points