Question

If 5.00 L of argon gas is at 0.460 atm and -123°C, what is the volume at STP?

Answer 1

4.27 L

Step-by-step explanation:

STP = 0 C and 1 atm

P1V1/T1 = P2V2/T2 where T is in Kelvin

P1 V1 / T1 *T2/P2 = V2

.469 * 5 / ( 273.15-123) * 273.15/1 = V2 = 4.27 L