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PLS HELP:

Find the magnitude of an electric field located 7.00 cm from a source charge of - 11 nC. (1nC = 1 x 10-9 C). Will the field lines point toward or away from the source charge? Show your work and include an electric field diagram assuming the source is a point charge

User Kiky
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1 Answer

3 votes

Answer:

E=kQ/r*2

=(9. 10*9)(11.10*-9)/(0,07)*2

=20204 N. C*-1

The field lines will point towards the source charge because it is negatively charged.

User Shagun
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