Question

a simple pendulum of amplitude completes 24 oscillations in one minute. find the length of the string the pendulum bob is attached​

Answer 1

`frequency = (24 \: osc)/(60 \: sec) = 0.4 \: osc \: per \: sec`

`period = (1)/(frequency) = (1)/(0.4) = 2.5 \: sec \: per \: osc`

`t = 2\pi \sqrt{ (l)/(g) } \\ 2.5 = 2\pi \sqrt{ (l)/(9.8) } \\ (2.5)/(2\pi) = \sqrt{ (l)/(9.8) } \\ ( (2.5)/(2\pi) ) {}^(2) = (l)/(9.8)`

`l = ( (2.5)/(2\pi) ) {}^(2) * 9.8 = 1.55148 \: meters`