Answer:
If using complex numbers, or undefined if using all real numbers
Explanation:
Moving -8 to the left side of the eq by adding both sides by 8=
x^2-3x+8=0
The quad formula:
![(-b +- √(b^2-4ac))/(2a)](https://img.qammunity.org/2023/formulas/mathematics/high-school/acysvnv2msw4jawf8jp21sgjkdwzs91ddd.png)
a=1 b=-3 c=8
Inserting a b c values into formula:
![(-(-3) +- √((-3)^2-4(1)(8)))/(2(1))](https://img.qammunity.org/2023/formulas/mathematics/high-school/q9122g8rz3cbw56d5hyk4cf2hseodk0mn3.png)
Simplifying:
Since the square root of a negative number doesn't exist in the set of real numbers, the equation is undefined.
OR
Using complex numbers i, to replace the negative number created by subtracting 9-32.