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What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 times a times c all over 2 times a? (1 point)

x = the quantity of negative 5 plus or minus the square root of 3 all over 2


x = the quantity of 5 plus or minus the square root of 3 all over 2


x = the quantity of negative 5 plus or minus the square root of 53 all over 2


x = the quantity of 5 plus or minus the square root of 53 all over 2

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or-example-1
User Khoekman
by
3.4k points

1 Answer

5 votes

Answer:
x=(5 \pm √(53))/(2)

Explanation:


x^2 - 5x-7=0\\\\x=(-(-5) \pm √((-5)^2 - 4(1)(-7)))/(2(1))\\\\x=(5 \pm √(53))/(2)

User Vahid Kh
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5.2k points