Question

24. Write the equation of the line that has a slope of -1/5 and a y-intercept of 8 in standard

form. Ax+By=C "Hint: Write the equation in slope-intercept or point slope form first, then
re-write in standard form.

Answer 1

x + 5y = 40

Explanation:

the equation of the line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = -
`(1)/(5)` and c = 8 , then

y = -
`(1)/(5)` x + 8 ( multiply through by 5 to clear the fraction )

5y = - x + 40 ( add x to both sides )

x + 5y = 40 ← in standard form

Answer 2

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Answer:

See Below.

Explanation:

`\large\begin{gathered}\sf{First, \ let's \ write \ the \ equation \ in \ slope-intercept \ form.}\\\sf{ Slope-Intercept \ form \ is \curvearrowright} \\\boxed{y=mx+b}}\\\sf{Substitute \ the \ pieces \ of \ information \ we \ have \curvearrowright\\\sf{ y=-(1)/(5)x+8}\\\sf{Now, if \ we \ multiply \ the \ entire \ equation \ by \ 5, \ we'll \ have:} \\\sf{5y=-x+40}\\\sf{And \ finally, move \ \bf{x} \ \sf{to \ the \ left \ with \ the \ opposite \ sign: x+5y=40.}\end{gathered} \bigstar \\\bigstar`

Done!!

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`\overbrace{C}\underbrace{A}\overbrace{L}\underbrace{L}\overbrace{I}\underbrace{G}\overbrace{R}\underbrace{A}\overbrace{P}\underbrace{H}\overbrace{Y}`