Question

Find the slope of the straight line that passes through (–2, –4) and (3, –5).

A. m= -1/5
B. m = –1
C. m = 1/5
D. m = 1

Answer 1

Answer is A. m= -1/5
Step by step
To find slope, (y2-y1) over (x2-x1)
(-5)-(-4) over 3-(-2)
-1 over 5
m = -1/5

Answer 2

`\large\boxed{\textsf{A.}\ m=-(1)/(5)}`

We can use the slope formula, where our points are
`(x_1,y_1)` and
`(x_2,y_2)`:

`(y_2-y_1)/(x_2-x_1)`

This is also known as "rise over run" because it represents the change in vertical (
`y`) position divided by the change in horizontal (
`x`) position.

Substitute the values from the points given:

`((-5)-(-4))/(3-(-2))`

Subtract:

`\boxed{(-1)/(5)}`