(3,3p) and (4,p²+1) has gradient -1 find p

asked Apr 25, 2023 230k views

2 votes

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5 votes

$\frac{p {}^(2) + 1 - 3p }{4 - 3} = -1$

$p {}^(2) - 3p + 1 = -1$

$p {}^(2) - 3p +2 = 0$

(p-2)(p - 1) = 0

$p = 2 \: \: \: \: \: p = 1$

Mmatloka answered Apr 29, 2023