Question

The question is in the attached picture​

Answer 1

Answer:
`(1)/(3) \sin x^(3)+C`

Explanation:

Let
`u=x^3`. Then,
`3x^2 dx = du \longrightarrow x^2 dx =(1)/(3)du`

So, we can rewrite the original integral as

`(1)/(3) \int \cos u \text{ } du=(1)/(3) \sin u+C=(1)/(3) \sin x^(3)+C`