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What is the length of focal chord of the equation y^2 + 6y - 2x + 13 = 0?

1 Answer

2 votes

Answer:

2 units

Explanation:

The given equation graphs as a parabola that opens to the right. It can be written in the form ...

(4p)x = ay² +by +c

Interpreting the equation

When the equation is written in the form ...

(4p)x = ay² +by +c

The value of p is the focus-to-vertex distance. The length of the latus rectum (focal chord) is 4 times the value of p, so is the coefficient of x in the equation.

Application

Rewriting the given equation to the form shown above, we have ...

2x = y² +6y +13

That is, the value of 4p, the coefficient of x, is 2. The length of the focal chord is 2 units.

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