Question

HELP

The holding tanks are congruent in size, and both are in the shape of a cylinder that has been cut in half vertically. The bottom of the tank is a curved surface. What is the volume of both tanks if the radius of tank #1 is 15 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit.
Density Calculation:

Answer 1

• Radius=r=15ft
• Height=h=120ft

`\\ \tt\Rrightarrow V=\pi r^2h`

`\\ \tt\Rrightarrow V=(22)/(7)(15)^2(120)`

`\\ \tt\Rrightarrow V=(22)/(7)(225)(120)`

`\\ \tt\Rrightarrow V=42390ft^3`

Answer 2

• 42390 ft³

Explanation:

Since the tanks are congruent, they both have same volume.

If you rejoin them, it will form a cylinder with the radius of 15 ft and height of 120 ft.

The volume of the cylinder:

• V = πr²h = 3.14*15²*120 = 84780 ft³

The volume of each tank is half the volume of the cylinder:

• V(tank) = 84780 / 2 = 42390 ft³