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33 votes
33 votes
Calculate the side lengths a and b to two decimal places.

A. a = 11.40 and b= 13.38
B. a = 11 and b = 15
C. a = 4.18 and b = 3.15
D. a = 10.92 and b= 14.52

Calculate the side lengths a and b to two decimal places. A. a = 11.40 and b= 13.38 B-example-1
User Roalz
by
2.8k points

2 Answers

24 votes
24 votes

Answer:

A.)=24.78

B.)=26

C.)=7.33

D.)=25.44

Explanation:

A.)11.40+13.38=24.78

B.)11+15=26

C.)4.18+3.15=7.33

D.)10.92+14.52=25.44

User Christopher Nolan
by
2.4k points
25 votes
25 votes

Answer:

D

Explanation:

Using the Sine rule to find a and b

We require to find ∠ C

∠ C = 180° - (115 + 43)° = 180° - 158° = 22°

Then


(a)/(sinA) =
(c)/(sinC) , substitute values


(a)/(sin43) =
(6)/(sin22) ( cross- multiply )

a × sin22° = 6 × sin43° ( divide both sides by sin22° )

a =
(6sin43)/(sin22) ≈ 10.92 ( to 2 dec. places )

---------------------------------------------------------


(b)/(sinB) =
(c)/(sinC) , that is


(b)/(sin115) =
(6)/(sin22) ( cross- multiply )

b × sin22° = 6 × sin115° ( divide both sides by sin22° )

b =
(6sin115)/(sin22) ≈ 14.52 ( to 2 dec. places )

User Oetoni
by
3.6k points