Question

I’m confused on this

Answer 1

x = 25

Explanation:

The mistake here is the squaring. When you square one side, you have to do the same on the other side:

`√(3x+6)` = 9

`(√(3x+6)) ^(2)` =
`9^(2)`

3x + 6 = 81

3x = 75

x = 25

Answer 2

`\huge\boxed{x=25}`

The mistake is in Step 1. The solver should have also squared
`9` when squaring the other side of the equation.

Correctly solving

`\begin{aligned}√(3x+6)&=9\\(√(3x+6))^2&=9^2\\3x+6&=81\\3x+6-6&=81-6\\3x&=75\\(3x)/(3)&=(75)/(3)\\x&=25\end{aligned}`