Step-by-step explanation:
Soln:-
Given:-
Volume(v)=5.0cm^3
mass(m)=13.5 gm
density (d)=?
We know that,
d=m÷v
=(13.5÷5)g/cm^3
=2.7g/cm^3
Hence, the required density of aluminum is 2.7g/cm^3.
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