Answer:
28.31
Explanation:
So in this case you're going to need to use the law of sines which essentially states that:
which should apply to any of the sides. the lowercase a and b are the opposite sides of the angles A and B. In this example the angle A is given and C is given, but not in the text. Since you have the right angle thing in the diagram, angle C is a right angle (90 degrees).
Given information:
![\angle A = 32\\a=15\\\angle C = 90 \text{(the right angle symbol in the diagram of the triangle)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ds54ktzhezomjcp28vbk061ql0pw1vq5hy.png)
Law of sines equation:
![(a)/(sinA)=(b)/(sinB) \text{ can be applied to any two sides }](https://img.qammunity.org/2023/formulas/mathematics/high-school/fd3amc2wc75r5otyyt2ovznxoqvswbcjqa.png)
Plug in known information:
![(15)/(sin(32))=(c)/(sin (90))](https://img.qammunity.org/2023/formulas/mathematics/high-school/a5xo9pwr8a7kgh87re8u5iahnngme5nnsg.png)
since sin(90) = 1, simplify the fraction
![(15)/(sin(32)) = c](https://img.qammunity.org/2023/formulas/mathematics/high-school/k5zvlv4vqj3r9sw2j0cz2scstvm6bef3ea.png)
Calculate sin(32)
![(15)/(0.530)\approx c](https://img.qammunity.org/2023/formulas/mathematics/high-school/f9lryoex8xm29zj5pl02rn0emzctedhup3.png)
Divide
![28.306\approx c](https://img.qammunity.org/2023/formulas/mathematics/high-school/2fr1hl1zfkw97dn4cdkum4ltpgai4h412p.png)
If you haven't learned law of sines yet and don't quite understand why it works you can also use the definition of tan to find what b equals and then use the Pythagorean Theorem to solve for c
tan is defined as:
![(opposite)/(adjacent)](https://img.qammunity.org/2023/formulas/mathematics/high-school/s4txkpzgzs7bsugu33qehqua7a2uwgny54.png)
![tan(32)=(15)/(b)](https://img.qammunity.org/2023/formulas/mathematics/high-school/ip3hrdfwvnjecs1b0uxxytlouskqnz41lg.png)
now multiply both sides by b
![b * tan(32)=15](https://img.qammunity.org/2023/formulas/mathematics/high-school/hfpb7irmtjo13jv0k57xp3jvkr9d32a2vc.png)
Divide both sides by tan 32
![b = (15)/(tan(32))](https://img.qammunity.org/2023/formulas/mathematics/high-school/ss2vxsb0vldw1el6e26ztwgc77b4ev9pds.png)
![b\approx 24.005](https://img.qammunity.org/2023/formulas/mathematics/high-school/r7a5w6zjqp5p5qy15oymv5dzsbgw9w9jia.png)
Now use the Pythagorean Theorem:
![a^2+b^2=c^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/fdnnfwrccw5g60jmi691r5gcz9ekxf8waa.png)
![(24.005)^2+15^2=c^2\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/5609rof6roga1sw8bhmvehyzbs4nzithwg.png)
Square known values
![576.241+225=c^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/gr75yrvuanxy0n1052jexhhpxtjj9uxhl9.png)
Add the values
![801.241 = c^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/1o6fi97zdgnylhsb1dy5gundq6jlhtlgac.png)
take the square root of both sides
![28.306\approx c](https://img.qammunity.org/2023/formulas/mathematics/high-school/2fr1hl1zfkw97dn4cdkum4ltpgai4h412p.png)
Rounding to the nearest hundredth gives you 28.31