118k views
4 votes
Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two thirds the distance from point P to point R.

4.9
4.7
2.5
2.3

User Bubble
by
8.4k points

1 Answer

0 votes

Answer:

4.7

Step-by-step explanation:

A point is positioned at minus two, seven. At one, zero, you'll find point R. Determine the value of Y. Regarding point Q. That is 2/3 of the distance between points P. So, negative two becomes positive seven. So, we have minus twenty-seven and 1 common zero. So, if we place a line between these, we must calculate the distance. First, you should be aware that you may achieve this using the distance formula. I prefer to conceive of it as the Pythagorean Theorem. So, the distance is 3^2 and 7^2, which is D^2. So, 9+49=58. And, we'll take the square root of it. As a result, the square root of 58=D. And, you want to be 2/3 the distance between points P and B. So, divide this by 2/3. So, this is close to 5.1. But, you want to get the Y value; found the distance, 2/3 of the way. When the distance is 5.1 instead of round 7.6, we've arrived at point P. We want to be 5. 1 yard away on this line. This is point P and we want to be at point Q. Since it'll have the same slope. As a result, the slope will be 7/3. So, it'll be proportionate 7. Since the square root of fifty-eight is too large. Route 58/3 is the destination. The square root of 258 is canceled. Such that 7=3y/2. 7x2=14/3=4.7. It's by locating comparable figures.

User Natie
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories