Question

Six bleeps equal 13 floops, and 2 floops equal 5 geebles. Based on this, 1 bleep is equal to N geebles. The integer closest to N is

A. 1
B. 2
C. 3
D. 4
E. 5

Answer 1

Explanation:

Solve from the least onwards

• 2floops are 5geebles
• 1 floop is 5/2geebles

Then

• 13floops are 65/2geebles

So

• 6bleeps are 65/2geebles
• 1 bleep is 65/12=5.4

5 is correct most

Option E

Answer 2

E. 5

Explanation:

Define the variables:

• Let b = bleeps
• Let f = floops
• Let g = geebles

Given information:

• Six bleeps equal 13 floops
• 2 floops equal 5 geebles

Use the given information and the defined variables to create two equations:

`\implies \sf 6b = 13f`

`\implies \sf 2f = 5g`

Rewrite the second equation to isolate f:

`\implies \sf (2f)/(2)=(5g)/(2)`

`\implies \sf f = 2.5g`

Substitute this into the first equation to get an expression with just bleeps and geebles:

`\implies \sf 6b = 13(2.5g)`

`\implies \sf 6b = 32.5g`

Finally, divide both sides by 6 to isolate b:

`\implies \sf (6b)/(6)=(32.5g)/(6)`

`\implies \sf b=5.42g\;(2\:d.p.)`

Round 5.42 to the nearest integer → 5

Therefore, N = 5